使用Paramiko在python中通过ssh实现交互式shell?
问题描述
我想编写一个程序(在Windows 7的Python 3.x中),通过ssh在远程shell上执行多个命令.看了paramikos的exec_command()
函数之后,我意识到它不适合我的用例(因为在执行命令后通道被关闭了),因为命令取决于环境变量(由先前的命令设置),并且不能连接到一个exec_command()
调用中,因为它们将在程序中的不同时间执行.
因此,我想在同一通道中执行命令.我研究的下一个选项是使用paramikos的invoke_shell()
函数实现交互式shell:
ssh = paramiko.SSHClient()
ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
ssh.connect(host, username=user, password=psw, port=22)
channel = ssh.invoke_shell()
out = channel.recv(9999)
channel.send('cd mivne_final\n')
channel.send('ls\n')
while not channel.recv_ready():
time.sleep(3)
out = channel.recv(9999)
print(out.decode("ascii"))
channel.send('cd ..\n')
channel.send('cd or_fail\n')
channel.send('ls\n')
while not channel.recv_ready():
time.sleep(3)
out = channel.recv(9999)
print(out.decode("ascii"))
channel.send('cd ..\n')
channel.send('cd simulator\n')
channel.send('ls\n')
while not channel.recv_ready():
time.sleep(3)
out = channel.recv(9999)
print(out.decode("ascii"))
ssh.close()
此代码存在一些问题:
- 第一个
print
并不总是打印ls
输出(有时仅打印在第二个print
上). - 第一个
cd
和ls
命令始终出现在输出中(我通过recv
命令获得它们,作为输出的一部分),而随后的所有cd
和ls
命令都是有时打印,有时不打印. - 第二个和第三个
cd
和ls
命令(在打印时)始终出现在第一个ls
输出之前.
我对这种不确定性"感到困惑,非常感谢您的帮助.
推荐答案
import paramiko
import re
class ShellHandler:
def __init__(self, host, user, psw):
self.ssh = paramiko.SSHClient()
self.ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
self.ssh.connect(host, username=user, password=psw, port=22)
channel = self.ssh.invoke_shell()
self.stdin = channel.makefile('wb')
self.stdout = channel.makefile('r')
def __del__(self):
self.ssh.close()
def execute(self, cmd):
"""
:param cmd: the command to be executed on the remote computer
:examples: execute('ls')
execute('finger')
execute('cd folder_name')
"""
cmd = cmd.strip('\n')
self.stdin.write(cmd + '\n')
finish = 'end of stdOUT buffer. finished with exit status'
echo_cmd = 'echo {} $?'.format(finish)
self.stdin.write(echo_cmd + '\n')
shin = self.stdin
self.stdin.flush()
shout = []
sherr = []
exit_status = 0
for line in self.stdout:
if str(line).startswith(cmd) or str(line).startswith(echo_cmd):
# up for now filled with shell junk from stdin
shout = []
elif str(line).startswith(finish):
# our finish command ends with the exit status
exit_status = int(str(line).rsplit(maxsplit=1)[1])
if exit_status:
# stderr is combined with stdout.
# thus, swap sherr with shout in a case of failure.
sherr = shout
shout = []
break
else:
# get rid of 'coloring and formatting' special characters
shout.append(re.compile(r'(\x9B|\x1B\[)[0-?]*[ -/]*[@-~]').sub('', line).
replace('\b', '').replace('\r', ''))
# first and last lines of shout/sherr contain a prompt
if shout and echo_cmd in shout[-1]:
shout.pop()
if shout and cmd in shout[0]:
shout.pop(0)
if sherr and echo_cmd in sherr[-1]:
sherr.pop()
if sherr and cmd in sherr[0]:
sherr.pop(0)
return shin, shout, sherr